Integrand size = 29, antiderivative size = 180 \[ \int \sec (c+d x) (a+b \sec (c+d x))^3 (A+B \sec (c+d x)) \, dx=\frac {\left (8 a^3 A+12 a A b^2+12 a^2 b B+3 b^3 B\right ) \text {arctanh}(\sin (c+d x))}{8 d}+\frac {\left (16 a^2 A b+4 A b^3+3 a^3 B+12 a b^2 B\right ) \tan (c+d x)}{6 d}+\frac {b \left (20 a A b+6 a^2 B+9 b^2 B\right ) \sec (c+d x) \tan (c+d x)}{24 d}+\frac {(4 A b+3 a B) (a+b \sec (c+d x))^2 \tan (c+d x)}{12 d}+\frac {B (a+b \sec (c+d x))^3 \tan (c+d x)}{4 d} \]
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Time = 0.37 (sec) , antiderivative size = 180, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.207, Rules used = {4087, 4082, 3872, 3855, 3852, 8} \[ \int \sec (c+d x) (a+b \sec (c+d x))^3 (A+B \sec (c+d x)) \, dx=\frac {b \left (6 a^2 B+20 a A b+9 b^2 B\right ) \tan (c+d x) \sec (c+d x)}{24 d}+\frac {\left (8 a^3 A+12 a^2 b B+12 a A b^2+3 b^3 B\right ) \text {arctanh}(\sin (c+d x))}{8 d}+\frac {\left (3 a^3 B+16 a^2 A b+12 a b^2 B+4 A b^3\right ) \tan (c+d x)}{6 d}+\frac {(3 a B+4 A b) \tan (c+d x) (a+b \sec (c+d x))^2}{12 d}+\frac {B \tan (c+d x) (a+b \sec (c+d x))^3}{4 d} \]
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Rule 8
Rule 3852
Rule 3855
Rule 3872
Rule 4082
Rule 4087
Rubi steps \begin{align*} \text {integral}& = \frac {B (a+b \sec (c+d x))^3 \tan (c+d x)}{4 d}+\frac {1}{4} \int \sec (c+d x) (a+b \sec (c+d x))^2 (4 a A+3 b B+(4 A b+3 a B) \sec (c+d x)) \, dx \\ & = \frac {(4 A b+3 a B) (a+b \sec (c+d x))^2 \tan (c+d x)}{12 d}+\frac {B (a+b \sec (c+d x))^3 \tan (c+d x)}{4 d}+\frac {1}{12} \int \sec (c+d x) (a+b \sec (c+d x)) \left (12 a^2 A+8 A b^2+15 a b B+\left (20 a A b+6 a^2 B+9 b^2 B\right ) \sec (c+d x)\right ) \, dx \\ & = \frac {b \left (20 a A b+6 a^2 B+9 b^2 B\right ) \sec (c+d x) \tan (c+d x)}{24 d}+\frac {(4 A b+3 a B) (a+b \sec (c+d x))^2 \tan (c+d x)}{12 d}+\frac {B (a+b \sec (c+d x))^3 \tan (c+d x)}{4 d}+\frac {1}{24} \int \sec (c+d x) \left (3 \left (8 a^3 A+12 a A b^2+12 a^2 b B+3 b^3 B\right )+4 \left (16 a^2 A b+4 A b^3+3 a^3 B+12 a b^2 B\right ) \sec (c+d x)\right ) \, dx \\ & = \frac {b \left (20 a A b+6 a^2 B+9 b^2 B\right ) \sec (c+d x) \tan (c+d x)}{24 d}+\frac {(4 A b+3 a B) (a+b \sec (c+d x))^2 \tan (c+d x)}{12 d}+\frac {B (a+b \sec (c+d x))^3 \tan (c+d x)}{4 d}+\frac {1}{6} \left (16 a^2 A b+4 A b^3+3 a^3 B+12 a b^2 B\right ) \int \sec ^2(c+d x) \, dx+\frac {1}{8} \left (8 a^3 A+12 a A b^2+12 a^2 b B+3 b^3 B\right ) \int \sec (c+d x) \, dx \\ & = \frac {\left (8 a^3 A+12 a A b^2+12 a^2 b B+3 b^3 B\right ) \text {arctanh}(\sin (c+d x))}{8 d}+\frac {b \left (20 a A b+6 a^2 B+9 b^2 B\right ) \sec (c+d x) \tan (c+d x)}{24 d}+\frac {(4 A b+3 a B) (a+b \sec (c+d x))^2 \tan (c+d x)}{12 d}+\frac {B (a+b \sec (c+d x))^3 \tan (c+d x)}{4 d}-\frac {\left (16 a^2 A b+4 A b^3+3 a^3 B+12 a b^2 B\right ) \text {Subst}(\int 1 \, dx,x,-\tan (c+d x))}{6 d} \\ & = \frac {\left (8 a^3 A+12 a A b^2+12 a^2 b B+3 b^3 B\right ) \text {arctanh}(\sin (c+d x))}{8 d}+\frac {\left (16 a^2 A b+4 A b^3+3 a^3 B+12 a b^2 B\right ) \tan (c+d x)}{6 d}+\frac {b \left (20 a A b+6 a^2 B+9 b^2 B\right ) \sec (c+d x) \tan (c+d x)}{24 d}+\frac {(4 A b+3 a B) (a+b \sec (c+d x))^2 \tan (c+d x)}{12 d}+\frac {B (a+b \sec (c+d x))^3 \tan (c+d x)}{4 d} \\ \end{align*}
Time = 0.68 (sec) , antiderivative size = 140, normalized size of antiderivative = 0.78 \[ \int \sec (c+d x) (a+b \sec (c+d x))^3 (A+B \sec (c+d x)) \, dx=\frac {3 \left (8 a^3 A+12 a A b^2+12 a^2 b B+3 b^3 B\right ) \text {arctanh}(\sin (c+d x))+\tan (c+d x) \left (24 \left (3 a^2 A b+A b^3+a^3 B+3 a b^2 B\right )+9 b \left (4 a A b+4 a^2 B+b^2 B\right ) \sec (c+d x)+6 b^3 B \sec ^3(c+d x)+8 b^2 (A b+3 a B) \tan ^2(c+d x)\right )}{24 d} \]
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Time = 4.84 (sec) , antiderivative size = 185, normalized size of antiderivative = 1.03
method | result | size |
parts | \(-\frac {\left (A \,b^{3}+3 B a \,b^{2}\right ) \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )}{d}+\frac {\left (3 A a \,b^{2}+3 B \,a^{2} b \right ) \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )}{d}+\frac {\left (3 A \,a^{2} b +B \,a^{3}\right ) \tan \left (d x +c \right )}{d}+\frac {A \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right ) a^{3}}{d}+\frac {B \,b^{3} \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )}{d}\) | \(185\) |
derivativedivides | \(\frac {a^{3} A \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+B \,a^{3} \tan \left (d x +c \right )+3 A \,a^{2} b \tan \left (d x +c \right )+3 B \,a^{2} b \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+3 A a \,b^{2} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )-3 B a \,b^{2} \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )-A \,b^{3} \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )+B \,b^{3} \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )}{d}\) | \(223\) |
default | \(\frac {a^{3} A \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+B \,a^{3} \tan \left (d x +c \right )+3 A \,a^{2} b \tan \left (d x +c \right )+3 B \,a^{2} b \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+3 A a \,b^{2} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )-3 B a \,b^{2} \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )-A \,b^{3} \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )+B \,b^{3} \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )}{d}\) | \(223\) |
parallelrisch | \(\frac {-96 \left (a^{3} A +\frac {3}{2} A a \,b^{2}+\frac {3}{2} B \,a^{2} b +\frac {3}{8} B \,b^{3}\right ) \left (\frac {3}{4}+\frac {\cos \left (4 d x +4 c \right )}{4}+\cos \left (2 d x +2 c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )+96 \left (a^{3} A +\frac {3}{2} A a \,b^{2}+\frac {3}{2} B \,a^{2} b +\frac {3}{8} B \,b^{3}\right ) \left (\frac {3}{4}+\frac {\cos \left (4 d x +4 c \right )}{4}+\cos \left (2 d x +2 c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+\left (144 A \,a^{2} b +64 A \,b^{3}+48 B \,a^{3}+192 B a \,b^{2}\right ) \sin \left (2 d x +2 c \right )+\left (72 A \,a^{2} b +16 A \,b^{3}+24 B \,a^{3}+48 B a \,b^{2}\right ) \sin \left (4 d x +4 c \right )+72 b \left (\left (A a b +B \,a^{2}+\frac {1}{4} b^{2} B \right ) \sin \left (3 d x +3 c \right )+\sin \left (d x +c \right ) \left (A a b +B \,a^{2}+\frac {11}{12} b^{2} B \right )\right )}{24 d \left (\cos \left (4 d x +4 c \right )+4 \cos \left (2 d x +2 c \right )+3\right )}\) | \(282\) |
norman | \(\frac {-\frac {\left (24 A \,a^{2} b -12 A a \,b^{2}+8 A \,b^{3}+8 B \,a^{3}-12 B \,a^{2} b +24 B a \,b^{2}-5 B \,b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{7}}{4 d}+\frac {\left (24 A \,a^{2} b +12 A a \,b^{2}+8 A \,b^{3}+8 B \,a^{3}+12 B \,a^{2} b +24 B a \,b^{2}+5 B \,b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{4 d}+\frac {\left (216 A \,a^{2} b -36 A a \,b^{2}+40 A \,b^{3}+72 B \,a^{3}-36 B \,a^{2} b +120 B a \,b^{2}+9 B \,b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{12 d}-\frac {\left (216 A \,a^{2} b +36 A a \,b^{2}+40 A \,b^{3}+72 B \,a^{3}+36 B \,a^{2} b +120 B a \,b^{2}-9 B \,b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{12 d}}{\left (-1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{4}}-\frac {\left (8 a^{3} A +12 A a \,b^{2}+12 B \,a^{2} b +3 B \,b^{3}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{8 d}+\frac {\left (8 a^{3} A +12 A a \,b^{2}+12 B \,a^{2} b +3 B \,b^{3}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{8 d}\) | \(357\) |
risch | \(-\frac {i \left (-72 A \,a^{2} b -48 B a \,b^{2}-24 B \,a^{3} {\mathrm e}^{6 i \left (d x +c \right )}+9 B \,b^{3} {\mathrm e}^{7 i \left (d x +c \right )}+33 B \,b^{3} {\mathrm e}^{5 i \left (d x +c \right )}-64 A \,b^{3} {\mathrm e}^{2 i \left (d x +c \right )}-72 B \,a^{3} {\mathrm e}^{2 i \left (d x +c \right )}-9 b^{3} B \,{\mathrm e}^{i \left (d x +c \right )}-72 B \,a^{3} {\mathrm e}^{4 i \left (d x +c \right )}-48 A \,b^{3} {\mathrm e}^{4 i \left (d x +c \right )}-33 B \,b^{3} {\mathrm e}^{3 i \left (d x +c \right )}-24 B \,a^{3}-144 B a \,b^{2} {\mathrm e}^{4 i \left (d x +c \right )}-36 A a \,b^{2} {\mathrm e}^{3 i \left (d x +c \right )}-36 B \,a^{2} b \,{\mathrm e}^{3 i \left (d x +c \right )}-36 A a \,b^{2} {\mathrm e}^{i \left (d x +c \right )}-36 B \,a^{2} b \,{\mathrm e}^{i \left (d x +c \right )}+36 A a \,b^{2} {\mathrm e}^{5 i \left (d x +c \right )}+36 B \,a^{2} b \,{\mathrm e}^{5 i \left (d x +c \right )}-216 A \,a^{2} b \,{\mathrm e}^{4 i \left (d x +c \right )}+36 A a \,b^{2} {\mathrm e}^{7 i \left (d x +c \right )}+36 B \,a^{2} b \,{\mathrm e}^{7 i \left (d x +c \right )}-72 A \,a^{2} b \,{\mathrm e}^{6 i \left (d x +c \right )}-216 A \,a^{2} b \,{\mathrm e}^{2 i \left (d x +c \right )}-192 B a \,b^{2} {\mathrm e}^{2 i \left (d x +c \right )}-16 A \,b^{3}\right )}{12 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{4}}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) a^{3} A}{d}+\frac {3 \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) A a \,b^{2}}{2 d}+\frac {3 \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) B \,a^{2} b}{2 d}+\frac {3 \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) B \,b^{3}}{8 d}-\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) a^{3} A}{d}-\frac {3 \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) A a \,b^{2}}{2 d}-\frac {3 \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) B \,a^{2} b}{2 d}-\frac {3 \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) B \,b^{3}}{8 d}\) | \(570\) |
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Time = 0.28 (sec) , antiderivative size = 211, normalized size of antiderivative = 1.17 \[ \int \sec (c+d x) (a+b \sec (c+d x))^3 (A+B \sec (c+d x)) \, dx=\frac {3 \, {\left (8 \, A a^{3} + 12 \, B a^{2} b + 12 \, A a b^{2} + 3 \, B b^{3}\right )} \cos \left (d x + c\right )^{4} \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \, {\left (8 \, A a^{3} + 12 \, B a^{2} b + 12 \, A a b^{2} + 3 \, B b^{3}\right )} \cos \left (d x + c\right )^{4} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \, {\left (6 \, B b^{3} + 8 \, {\left (3 \, B a^{3} + 9 \, A a^{2} b + 6 \, B a b^{2} + 2 \, A b^{3}\right )} \cos \left (d x + c\right )^{3} + 9 \, {\left (4 \, B a^{2} b + 4 \, A a b^{2} + B b^{3}\right )} \cos \left (d x + c\right )^{2} + 8 \, {\left (3 \, B a b^{2} + A b^{3}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{48 \, d \cos \left (d x + c\right )^{4}} \]
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\[ \int \sec (c+d x) (a+b \sec (c+d x))^3 (A+B \sec (c+d x)) \, dx=\int \left (A + B \sec {\left (c + d x \right )}\right ) \left (a + b \sec {\left (c + d x \right )}\right )^{3} \sec {\left (c + d x \right )}\, dx \]
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Time = 0.22 (sec) , antiderivative size = 266, normalized size of antiderivative = 1.48 \[ \int \sec (c+d x) (a+b \sec (c+d x))^3 (A+B \sec (c+d x)) \, dx=\frac {48 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} B a b^{2} + 16 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} A b^{3} - 3 \, B b^{3} {\left (\frac {2 \, {\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 36 \, B a^{2} b {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 36 \, A a b^{2} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 48 \, A a^{3} \log \left (\sec \left (d x + c\right ) + \tan \left (d x + c\right )\right ) + 48 \, B a^{3} \tan \left (d x + c\right ) + 144 \, A a^{2} b \tan \left (d x + c\right )}{48 \, d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 586 vs. \(2 (170) = 340\).
Time = 0.35 (sec) , antiderivative size = 586, normalized size of antiderivative = 3.26 \[ \int \sec (c+d x) (a+b \sec (c+d x))^3 (A+B \sec (c+d x)) \, dx=\frac {3 \, {\left (8 \, A a^{3} + 12 \, B a^{2} b + 12 \, A a b^{2} + 3 \, B b^{3}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - 3 \, {\left (8 \, A a^{3} + 12 \, B a^{2} b + 12 \, A a b^{2} + 3 \, B b^{3}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) - \frac {2 \, {\left (24 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 72 \, A a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 36 \, B a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 36 \, A a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 72 \, B a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 24 \, A b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 15 \, B b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 72 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 216 \, A a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 36 \, B a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 36 \, A a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 120 \, B a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 40 \, A b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 9 \, B b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 72 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 216 \, A a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 36 \, B a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 36 \, A a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 120 \, B a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 40 \, A b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 9 \, B b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 24 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 72 \, A a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 36 \, B a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 36 \, A a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 72 \, B a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 24 \, A b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 15 \, B b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{4}}}{24 \, d} \]
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Time = 18.07 (sec) , antiderivative size = 395, normalized size of antiderivative = 2.19 \[ \int \sec (c+d x) (a+b \sec (c+d x))^3 (A+B \sec (c+d x)) \, dx=\frac {\mathrm {atanh}\left (\frac {4\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (A\,a^3+\frac {3\,B\,a^2\,b}{2}+\frac {3\,A\,a\,b^2}{2}+\frac {3\,B\,b^3}{8}\right )}{4\,A\,a^3+6\,B\,a^2\,b+6\,A\,a\,b^2+\frac {3\,B\,b^3}{2}}\right )\,\left (2\,A\,a^3+3\,B\,a^2\,b+3\,A\,a\,b^2+\frac {3\,B\,b^3}{4}\right )}{d}-\frac {\left (2\,A\,b^3+2\,B\,a^3-\frac {5\,B\,b^3}{4}-3\,A\,a\,b^2+6\,A\,a^2\,b+6\,B\,a\,b^2-3\,B\,a^2\,b\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7+\left (3\,A\,a\,b^2-6\,B\,a^3-\frac {3\,B\,b^3}{4}-\frac {10\,A\,b^3}{3}-18\,A\,a^2\,b-10\,B\,a\,b^2+3\,B\,a^2\,b\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+\left (\frac {10\,A\,b^3}{3}+6\,B\,a^3-\frac {3\,B\,b^3}{4}+3\,A\,a\,b^2+18\,A\,a^2\,b+10\,B\,a\,b^2+3\,B\,a^2\,b\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3+\left (-2\,A\,b^3-2\,B\,a^3-\frac {5\,B\,b^3}{4}-3\,A\,a\,b^2-6\,A\,a^2\,b-6\,B\,a\,b^2-3\,B\,a^2\,b\right )\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8-4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+6\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4-4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )} \]
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